Safecracker Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 4797 Accepted Submission(s): 2405 Problem Description ...=== Op tech briefi
Safecracker Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 4797 Accepted Submission(s): 2405 Problem Description ...=== Op tech briefi
#include #include #include int vis[15], in[15]; char str[15], ans[15]; int chen, len; int cmp(const void *a, const void *b) { return *(char *)b-*(char *)a; } int dfs(int num) ...
本来是考察搜索的,结果五重循环竟然就AC了。。。 #include #include #include ...int EQ(int x,int y,int z,int p,int q,int t) ... if(x-y*y+z*z*z-p*p*p*p+q*q*q*q*q==t) return 1;...int cmp(const void *a,c
Safecracker Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 6937 Accepted Submission(s): 3445 Problem Description ...=== Op tech brie
Problem Description === Op tech briefing, 2002/11/02 06:42 CST === "The item is locked in a Klein safe behind a painting in the second-floor library. Klein safes are extremely rare;...
Safecracker Time Limit : 2000/1000ms (Java/Other)Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 3Accepted Submission(s) : 1 Problem Description === Op tech briefing, 2...
Safe Or Unsafe Time Limit : 2000/1000ms (Java/Other) Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 18 Accepted Submission(s) : 13 Problem Description Javac++ 一天在看计算机的书籍的...
有用六重循环的,无敌了。。。 以下代码采用回溯法。 #include #include #include #include using namespace std; bool visit[30] ,judge; int ans[6] ,N[26] ,total; long long target ,sum;... for(i
Safecracker Time Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6494Accepted Submission(s): 3238 Problem Description === Op tech briefing, 20...
题目链接http://acm.hdu.edu.cn/showproblem.php?pid=1015 题目的大意就是给以一串字符串和一个目标数字,让你从中找出5个字母,依次可以满足v - w^2 + x^3 - y^4 + z^5 = target这个关系式 如果有多个就按字典序...
此题恶心啊,20分钟的代码,硬是写了2个半小时,最后终于出来了, 题意: 你要得到一个序列 满足 一个关系式; 思路: 枚举排列,然后保存字典序最大的(就是这个恶心啊,,受不鸟,2,个小时啊,代码啊代码) ...
http://acm.hdu.edu.cn/showproblem.php?pid=1015 Safecracker Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 6327 Accepted Submissi...
#include #include using namespace std; const int maxn=30+5; char s[maxn],l[maxn],r[maxn]; int len,tar,sum,st; bool flag,vis[maxn]; void dfs() { if(st) { for(int i=0; i; i++)
Safecracker Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 5180 Accepted Submission(s): 2600 Problem Description ...=== Op tech...
Safecracker Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3713 Accepted Submission(s): 1919 Problem Description === Op tech briefing, 20...
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1015 题目说是从一个字符串中找到5个数 v w x y z 给定target (子母中 A=1 ,B=2,C=3。。。Z=26) v - w^2 + x^3 - y^4 + z^5 = target 题目中有一个要求:...
Safecracker Time Limit : 2000/1000ms (Java/Other) Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 3 Accepted Submission(s) : 1 Problem Description === Op tech briefing, 2002/11
题目链接 普通的DFS。。。输出字典序最大的。。。我竟然没注意。。 #include <stdio.h> #include <string.h> char p[31],o[31],max[31]; int k[31]; int ans,z,len;... if(step...
地址:http://acm.hdu.edu.cn/showproblem.php?pid=1015 题意:在给定字符集中选5个字符(v,w,x,y,z)使得满足v - w^2 + x^3 - y^4 + z^5 = target。输出字典序最大的一个。 mark:dfs。1WA。一开始以为是字符集中...
题目; === Op tech briefing, 2002/11/02 06:42 CST === "The item is locked in a Klein safe behind a painting in the second-floor library. Klein safes are extremely rare; most of them, along with Klein ...
Safecracker Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 4398 Accepted Submission(s): 2221 Problem Description ...=== Op tech brie
问题描述:=== Op tech briefing, 2002/11/02 06:42 CST === "The item is locked in a Klein safe behind a painting in the second-floor library. Klein safes are extremely rare; most of them, along with ...
首先表示刚发的那个hdu题目分类各种不准!! 按顺序看到1015高精度就打开来看看,结果水题一道。好吧,就算我过了,我真心得不是故意的。 1250是高精度加法,加法比较容易搞定啦,很快写完却MLE,于是不得不用四位...
http://acm.hdu.edu.cn/showproblem.php?pid=1015 题目输入多组数据第组包括:一个整数n和一个字符串,要求从字符串中,选五个字串且满足v - w^2 + x^3 - y^4 + z^5 = n; c++ #include <stdio.h>#include&...
http://acm.hdu.edu.cn/showproblem.php?pid=1050 /* 2011-9-8 author:BearFly1990 */ package acm.hdu.tests; import java.io.BufferedInputStream
#include <iostream> #include <cstdio> #include <algorithm> #include <string> #include <functional> using namespace std; bool flag; //递归标志 char str[27]; char ans[6]; bool vis[27];...
#include #include #include #include using namespace std; int main() { int n,i,j,k,l,m,sum,sum1,sum2,sum3,sum4,sum5,flag; char v,w,x,y,z; char dest[30],turn[30]; while(1) {